CBSE Class 10 Maths: Introduction to Trigonometry Ex 8.3
Welcome to Exercise 8.3 of "Introduction to Trigonometry" for CBSE Class 10! In this crucial section, we dive into the fascinating world of trigonometric ratios of complementary angles. You've already built a strong foundation with basic trigonometric ratios; now, you'll discover how these ratios relate when angles add up to 90 degrees. Understanding these identities is key to simplifying complex trigonometric expressions and solving problems that don't involve standard angles like 30°, 45°, or 60°. By the end of this page, you'll not only grasp the core concepts of complementary angles but also master their application in various problem-solving scenarios, preparing you thoroughly for your board exams. Let's unlock the power of these identities together!
Understanding Trigonometric Ratios of Complementary Angles
In a right-angled triangle, if one acute angle is 'A', then the other acute angle must be (90° - A), because the sum of all angles in a triangle is 180°, and one angle is 90°. These two acute angles, A and (90° - A), are called complementary angles as their sum is 90°.
The beauty of trigonometry is how ratios of complementary angles are related. Let's consider a right-angled triangle ABC, right-angled at B. If ∠C = A, then ∠A = 90° - A.
Now, let's look at the ratios:
- sin A = Opposite/Hypotenuse = AB/AC
- cos (90° - A) = Adjacent/Hypotenuse = AB/AC
This clearly shows that sin A = cos (90° - A). Similarly, by observing the other sides and ratios, we can derive the following fundamental identities for complementary angles:
-
sin (90° - A) = cos A -
cos (90° - A) = sin A -
tan (90° - A) = cot A -
cot (90° - A) = tan A -
sec (90° - A) = cosec A -
cosec (90° - A) = sec A
These identities are incredibly useful for simplifying trigonometric expressions, especially when you encounter angles that are not standard values but sum up to 90°. The trick is to identify such pairs and apply the appropriate transformation. For example, if you see sin 25° and cos 65°, you immediately know 25° + 65° = 90°, so cos 65° can be written as sin (90° - 65°) = sin 25°.
Step-by-Step Problem Solving with Complementary Angles
- Identify Complementary Angle Pairs — Look for angles in the given expression that add up to 90°. For example, (20°, 70°), (35°, 55°), etc. This is the first and most crucial step.
- Choose One Angle to Transform — For each complementary pair, decide which trigonometric ratio you want to convert. For instance, if you have
sin 20°andcos 70°, you can either changesin 20°tocos (90°-20°) = cos 70°or changecos 70°tosin (90°-70°) = sin 20°. The goal is to make the angles and/or the trigonometric functions match for simplification. - Apply the Correct Identity — Use the identities:
sin(90°-A)=cos A,cos(90°-A)=sin A,tan(90°-A)=cot A,cot(90°-A)=tan A,sec(90°-A)=cosec A,cosec(90°-A)=sec A. Ensure you don't confuse which ratio transforms into which. - Simplify the Expression — After applying the identities, simplify the expression. This might involve cancellation, addition/subtraction of like terms, or using other fundamental trigonometric identities (like
tan A = sin A / cos A,sec A = 1/cos A). - Verify (Optional but Recommended) — If time permits, especially for proving identities, quickly re-check your steps and calculations to ensure accuracy.
Worked Examples from Exercise 8.3
- Example 1: Evaluate tan 65° / cot 25°
Step 1: Notice that the angles 65° and 25° are complementary, as 65° + 25° = 90°.
Step 2: We can convert either tan 65° or cot 25°. Let's convert tan 65°.
Using the identity
tan (90° - A) = cot A, we havetan 65° = tan (90° - 25°) = cot 25°. Step 3: Substitute this into the original expression:tan 65° / cot 25° = cot 25° / cot 25°Step 4: Simplify the expression.cot 25° / cot 25° = 1Final Answer:1 - Example 2: If sin 3A = cos (A - 26°), where 3A is an acute angle, find the value of A.
Step 1: The given equation is
sin 3A = cos (A - 26°). We know thatsin θ = cos (90° - θ). Step 2: Apply the identity to the left side:sin 3A = cos (90° - 3A). Step 3: Now, equate the transformed expression with the right side of the original equation:cos (90° - 3A) = cos (A - 26°)Step 4: Since the cosine of two acute angles is equal, the angles themselves must be equal.90° - 3A = A - 26°Step 5: Solve for A.90° + 26° = A + 3A116° = 4AA = 116° / 4A = 29°Step 6: Verify if 3A is acute:3 * 29° = 87°, which is an acute angle. Final Answer:A = 29°
Common Mistakes and Exam Tips
- Confusing Identities: A very common mistake is to mix up which ratio converts to which. Remember:
sinandcosare complementary,tanandcotare complementary, andsecandcosecare complementary. Forgetting this can lead to incorrect substitutions (e.g.,sin(90-A) = sec A). - Incorrect Angle Subtraction: When using
(90° - A), ensure you subtract the angle correctly. For expressions like(A - 26°), be careful if you are transformingcos (A - 26°) = sin (90° - (A - 26°)) = sin (90° - A + 26°) = sin (116° - A). - Not Identifying Complementary Pairs: Sometimes students try to convert ratios where the angles are not complementary, making the problem harder or leading to wrong answers. Always check if the angles sum to 90° first.
- Leaving Unsimplified Expressions: After applying the identities, always simplify the expression to its lowest possible form. Don't stop halfway.
- Practice is Key: The best way to avoid these mistakes is consistent practice. Work through all the examples and exercises from your NCERT textbook and additional problems.
Practice Questions with Solutions
- Q: Evaluate: sin 18° / cos 72°
A: Step 1: Notice that 18° + 72° = 90°, so they are complementary angles.
A: Step 2: Convert
sin 18°using the identitysin (90° - A) = cos A. So,sin 18° = sin (90° - 72°) = cos 72°. A: Step 3: Substitute this into the expression:cos 72° / cos 72°. A: Step 4: Simplify the expression. Final answer:1 - Q: If tan 2A = cot (A - 18°), where 2A is an acute angle, find the value of A.
A: Step 1: The given equation is
tan 2A = cot (A - 18°). We know thattan θ = cot (90° - θ). A: Step 2: Apply the identity to the left side:tan 2A = cot (90° - 2A). A: Step 3: Equate the transformed expression with the right side:cot (90° - 2A) = cot (A - 18°). A: Step 4: Since cotangent of two acute angles is equal, the angles must be equal:90° - 2A = A - 18°. A: Step 5: Solve for A:90° + 18° = A + 2A=>108° = 3A=>A = 108° / 3. Final answer:A = 36° - Q: Show that tan 48° tan 23° tan 42° tan 67° = 1.
A: Step 1: Group complementary angle pairs:
(48°, 42°)because 48° + 42° = 90°; and(23°, 67°)because 23° + 67° = 90°. A: Step 2: Use the identitytan (90° - A) = cot A. A: Step 3: Converttan 48°tocot (90° - 48°) = cot 42°. A: Step 4: Converttan 23°tocot (90° - 23°) = cot 67°. A: Step 5: Substitute these into the expression:(cot 42°) (cot 67°) (tan 42°) (tan 67°). A: Step 6: Rearrange and usecot A = 1 / tan A:(cot 42° tan 42°) (cot 67° tan 67°) = (1) (1). Final answer:1(Hence proved) - Q: Express cosec 68° + cos 85° in terms of trigonometric ratios of angles between 0° and 45°.
A: Step 1: We need to convert 68° and 85° into angles between 0° and 45° using complementary angle identities.
A: Step 2: For
cosec 68°, usecosec (90° - A) = sec A. So,cosec 68° = cosec (90° - 22°) = sec 22°. A: Step 3: Forcos 85°, usecos (90° - A) = sin A. So,cos 85° = cos (90° - 5°) = sin 5°. A: Step 4: Substitute these converted terms back into the original expression. Final answer:sec 22° + sin 5°
Frequently Asked Questions
What are complementary angles in trigonometry?
In trigonometry, two angles are complementary if their sum is 90 degrees. For example, if one acute angle in a right-angled triangle is A, the other acute angle is (90° - A), making them complementary.
Why are trigonometric ratios of complementary angles important?
These identities are crucial for simplifying expressions involving angles that are not standard (like 30°, 45°, 60°) but are complementary to each other. They allow you to transform one ratio into another, making calculations and proofs much easier.
How do I remember the complementary angle identities?
Think of the 'co-function' relationships: `sine` is the co-function of `cosine`, `tangent` of `cotangent`, and `secant` of `cosecant`. Each function's co-function is its complementary angle counterpart (e.g., `sin A = cos (90°-A)`).
Can these identities be applied to angles outside the 0°-90° range?
While the derivation typically uses acute angles in a right triangle, the identities `sin(90°-A) = cos A`, etc., hold true for all values of A where the functions are defined, as long as (90°-A) and A are within the domain of the respective functions.