NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.1

Welcome, future math champions! In Class 10 Maths Chapter 2, one of the most visual and high-scoring topics is understanding the geometric meaning of the zeroes of a polynomial. Today, we are focusing on polynomials ex 2 1 class 10 ncert, which serves as your graphic foundation for this entire chapter. While you learned how to find polynomial zeroes algebraically in Class 9, Exercise 2.1 teaches you how to interpret them visually. By analyzing the graph of $y = p(x)$, you will quickly learn to identify the exact number of real zeroes simply by counting how many times the curve crosses or touches the horizontal x-axis. Mastering this graphical representation is not just a quick way to secure easy 1-mark board exam questions; it also develops your spatial intuition for coordinate geometry and advanced calculus. Let's master this topic step-by-step with your YoLearn AI Tutor!

The Geometric Meaning of Polynomial Zeroes

In algebra, a real number $k$ is called a zero of a polynomial $p(x)$ if $p(k) = 0$. Geometrically, this has a highly intuitive meaning. If we plot the graph of the equation $y = p(x)$ on a Cartesian coordinate plane, the zeroes of the polynomial are the x-coordinates of the points where the graph intersects or touches the x-axis.

Why does this happen? At any point on the x-axis, the y-coordinate is strictly zero. Since our graph represents $y = p(x)$, setting $y = 0$ is mathematically equivalent to solving the algebraic equation $p(x) = 0$. Therefore, every single point where the curve meets the x-axis represents a real value of $x$ that makes the polynomial equal to zero. For a linear polynomial $ax + b$ ($a \neq 0$), the graph is a straight line intersecting the x-axis at exactly one point, $(-b/a, 0)$. For a quadratic polynomial $ax^2 + bx + c$, the graph is a parabolic curve that can cross the x-axis at two points, touch it at one point, or completely miss it, representing two, one, or zero real zeroes respectively.

Step-by-Step: Counting Zeroes from a Graph

  1. Identify the Dependent Variable — Read the problem statement carefully to confirm if the function is defined as $y = p(x)$ or $x = p(y)$. For standard Class 10 Exercise 2.1 problems, we always analyze $y = p(x)$.
  2. Locate the Horizontal X-Axis — Focus your eyes strictly on the horizontal axis (the x-axis). You must completely ignore any points where the graph intersects the vertical y-axis.
  3. Trace the Curve — Follow the path of the given graph from left to right along the Cartesian plane.
  4. Count Intersections and Touchpoints — Count every distinct point where the curve cuts directly across the x-axis or gently touches the x-axis and reverses its direction.
  5. State the Final Number of Zeroes — The total number of these intersection and touching points is exactly equal to the number of real zeroes of the polynomial $p(x)$.

Beware of the Variable Swap Trap!

In board exams, examiners love to test your conceptual depth by switching the standard variables. While class 10 maths polynomials ex 2 1 exclusively deals with the polynomial equation $y = p(x)$, a tricky question might ask you to find the number of zeroes of a polynomial defined as $x = p(y)$.

If the equation is written as $x = p(y)$, the zeroes are the values of $y$ for which $x = 0$. In this specific scenario, you must count the number of times the curve intersects or touches the vertical y-axis, not the horizontal x-axis! Always read the notation carefully before writing your final answer.

Practice Questions with Solutions

  • Q: The graph of a linear polynomial $y = p(x)$ is a straight line parallel to the x-axis, passing through the point $(0, 4)$. Find the number of zeroes of $p(x)$. A: Step 1: Analyze the given line. A straight line parallel to the x-axis passing through $(0, 4)$ is represented by the equation $y = 4$. Step 2: Check for intersections with the x-axis. Since the line is completely parallel to the x-axis and lies 4 units above it, it will never cross or touch the x-axis. Step 3: Relate this to zeroes. Since there are 0 points of intersection with the x-axis, the polynomial has no real zeroes. Final answer: The number of zeroes of $p(x)$ is 0.
  • Q: A parabola opening upwards cuts the horizontal x-axis at the points $(-3, 0)$ and $(5, 0)$. How many zeroes does this quadratic polynomial have, and what are their values? A: Step 1: Identify all points of intersection with the x-axis. The curve intersects the x-axis at $(-3, 0)$ and $(5, 0)$. Step 2: Count the total number of intersection points, which is exactly 2. Step 3: Determine the zeroes. The x-coordinates of these intersection points are the zeroes of the polynomial. Thus, the zeroes are $x = -3$ and $x = 5$. Final answer: The number of zeroes is 2, and the zeroes are -3 and 5.
  • Q: The graph of a cubic polynomial $y = p(x)$ crosses the origin $(0,0)$, passes through $(-2, 0)$, and touches the x-axis at $(3, 0)$ before turning upwards. Find the number of zeroes of $p(x)$. A: Step 1: Identify all coordinate points where the graph meets the horizontal x-axis. The points are $(-2, 0)$, $(0, 0)$ (the origin), and $(3, 0)$. Step 2: Analyze the contact. The graph cuts across at $(-2, 0)$ and $(0, 0)$, and touches at $(3, 0)$. Both crossings and touchpoints count as geometric zeroes. Step 3: Sum up the points: $1 + 1 + 1 = 3$ points of contact. Final answer: The number of zeroes of $p(x)$ is 3.
  • Q: If a curve defined by $y = p(x)$ is positioned entirely below the x-axis and never rises above $y = -1$, find the number of real zeroes of the polynomial $p(x)$. A: Step 1: Visualize the position of the graph. The maximum value of $y$ on the curve is $-1$, which means the entire curve lies in the third and fourth quadrants. Step 2: Check for any contact with the horizontal axis. Since the curve stays below $y = -1$, it cannot touch or intersect the line $y = 0$ (the x-axis). Step 3: Conclude the number of zeroes. With zero intersections, there are no real zeroes. Final answer: The number of zeroes of $p(x)$ is 0.

Frequently Asked Questions

Why do we only look at the x-axis to find the zeroes of y = p(x)?

A zero of $p(x)$ is any value of $x$ that results in $p(x) = 0$. Since $y = p(x)$, we are looking for points on the graph where $y = 0$, which is the equation that defines the horizontal x-axis.

Can a quadratic polynomial have zero real zeroes?

Yes, a quadratic polynomial can have zero real zeroes. This occurs geometrically when its parabolic graph lies entirely above or below the x-axis without ever crossing or touching it.

What is the physical difference between a graph crossing the x-axis and touching it?

Crossing the x-axis means the polynomial changes sign from positive to negative. Touching the x-axis and turning back means it reaches zero but keeps the same sign, representing a repeated real root (even multiplicity).